The time period of simple pendulum when it is made to oscilate on the surface of moon

Question

Toppr Admin · Accepted Answer

Correct option is A- Increase-T-2-pi-sqrt-dfrac-l-g-left-as- T -propto -dfrac -1-sqrt g-right-At the surface of moon- -g- decrease hence time period increase-160-

The time period of simple pendulum when it is made to oscilate on the surface of moon

Correct option is A. Increase$$T=2\pi\sqrt{\dfrac{l}{g}}$$$$\left(as\ T \propto \dfrac {1}{\sqrt g}\right)$$At the surface of moon, $$g$$ decrease hence time period increase

Correct option is A. Increase
$$T=2\pi\sqrt{\dfrac{l}{g}}$$
$$\left(as\ T \propto \dfrac {1}{\sqrt g}\right)$$

At the surface of moon, $$g$$ decrease hence time period increase