The time taken by a particle performing SHM to pass from point A to B where its velocities are same is $2 s$ . After another $2 s$ , it returns to B.The time period of oscillation is

Question

The time taken by a particle performing SHM to pass from point A to B where its velocities are same is 2s- After another 2s- it returns to B-The time period of oscillation is4-s-8-s-6-s-10-s-

Toppr Admin · Accepted Answer

We see that the velocity at A and B are same and it takes $2$ s to cover this distance.
Now it takes $2$ s more to come back to B after travelling to the extreme position.
We see that the distance covered from A to B and then from B and then back to B from extreme takes $4$ s. This is half the distance in the whole top and fro path. Thus the time taken for one oscillation should be $8$ s

The time taken by a particle performing SHM to pass from point A to B where its velocities are same is 2s. After another 2s, it returns to B.The time period of oscillation is4s8s6s10s

The time taken by a particle performing SHM to pass from point A to B where its velocities are same is $2 s$ . After another $2 s$ , it returns to B.The time period of oscillation is
4 $s$
8 $s$
6 $s$
10 $s$