The time taken by a particle performing $S H M$ to pass from point $A$ to $B$ where its velocities are same is $2$ seconds.After another $2$ seconds it returns to $B$ . The time period of oscillation is (in seconds)

Question

The time taken by a particle performing

S H M

to pass from point

A

to

B

where its velocities are same is

2

seconds.After another

2

seconds it returns to

B

. The time period of oscillation is (in seconds)

Toppr Admin · Accepted Answer

According to the question- a and b points are such that they are-xA0-located at same distances from the equilibrium position-xA0-Here also it is said that velocity is same-xA0-i-e- not only the magnitude but also the directions are same-xA0-So- total time period of oscillation -2-xD7- time taken to go from a to b-xA0- the next time taken to return at b- -2-xD7-2-2-8 sec-

The time taken by a particle performing S.H.M. to pass from point A to B where its velocities are same is 2 seconds. After another 2 seconds it returns to B . The time period of oscillation is (in seconds):2468

The time taken by a particle performing S.H.M. to pass from point $A$ to $B$ where its velocities are same is $2$ seconds. After another 2 seconds it returns to $B$ . The time period of oscillation is (in seconds):
$2$
$4$
$6$
$8$