The torque and magnetic potential energy of a magnetic dipole in most stable position in a uniform magnetic field(¯B) having magnetic moment (¯m) will be.
−mB, zero
mB, zero
Zero, mB
Zero, −mB
A
mB, zero
B
−mB, zero
C
Zero, mB
D
Zero, −mB
Open in App
Solution
Verified by Toppr
The correct option is D Zero, −mB Torque, ¯τ=→m×→B=mBsinθ and magnetic potential energy Um=→m⋅→B=mBcosθ at θ=0o the dipole will be in most stable position τ=mBsinθ=mBsin0o=0 and Um=−mBcosθ=−mBcosθo=−mB
Was this answer helpful?
22
Similar Questions
Q1
The torque and magnetic potential energy of a magnetic dipole in most stable position in a uniform magnetic field(¯B) having magnetic moment (¯m) will be.
View Solution
Q2
The torque and magnetic potential energy of a magnetic dipole in most stable position in a uniform magnetic field of magnetic strength 5T, having magnetic moment μ=2Am2 will be
View Solution
Q3
A dipole of magnetic moment ¯m=30^jAm2 is placed along the y-axis in a uniform magnetic field ¯B=(2^i+5^j) T. The torque acting on it is
View Solution
Q4
A bar magnet is placed in the position of stable equilibrium in a uniform magnetic filed of induction B. If it is rotated through an angle 180∘ , then the work is: (M is magnetic dipole moment)
View Solution
Q5
The work done in moving a dipole from its most stable to most unstable position in a 0.09T uniform magnetic field is (dipole moment of this dipole = 0.5Am2)