The total number of electrons that take part in forming bonds in N-2 is-24610

Question

Toppr Admin · Accepted Answer

Structure of-xA0- N2 is N-x2261-N-In-xA0-N2 there are 3 bonds between two nitrogen atoms and each bond is formed by 2 electrons-xA0-So- 3 bonds make it-xA0-3-xD7-2-6 electrons in total-

The total number of electrons that take part in forming bonds in $N_{2}$ is:
2
4
6
10

Structure of $N_{2}$ is $N \equiv N .$

In $N_{2}$ there are 3 bonds between two nitrogen atoms and each bond is formed by 2 electrons.

So, 3 bonds make it $3 \times 2 = 6$ electrons in total.

The total number of electrons that take part in forming bonds in N2 is:24610

Structure of N2 is N≡N.In N2 there are 3 bonds between two nitrogen atoms and each bond is formed by 2 electrons. So, 3 bonds make it 3×2=6 electrons in total.

The total number of electrons that take part in forming bonds in $N_{2}$ is:
2
4
6
10

Structure of $N_{2}$ is $N \equiv N .$

In $N_{2}$ there are 3 bonds between two nitrogen atoms and each bond is formed by 2 electrons.

So, 3 bonds make it $3 \times 2 = 6$ electrons in total.