The uncertainity in position for a dust particle (m=10−11g ;diameter=10−4cm and velocity=10−11cm/s) will be: ( The error in measurement of velocity is 1%)
5.27×10−7cm
5.27×10−6cm
5.27×10−4cm
5.27×10−5cm
A
5.27×10−4cm
B
5.27×10−5cm
C
5.27×10−6cm
D
5.27×10−7cm
Open in App
Solution
Verified by Toppr
Δx = uncertainty in position
Heisenberg uncertainty equation is Δx(mΔv)=h/4π
Δv = 1% eroor in the velocity = 1×10−11/100×10−2=10−15 m = 10−14
10−15×10−14×Δx=6.626×10−344π
Δx=6.62610−54πm−1
or Δv=0.527×10−5
Δv=5.27×10−4
Was this answer helpful?
0
Similar Questions
Q1
The uncertainity in position for a dust particle (m=10−11g ;diameter=10−4cm and velocity=10−11cm/s) will be: ( The error in measurement of velocity is 1%)
View Solution
Q2
The uncertainity in momentum of an electron is 1×10−5kg.m/s. The uncertainity in its position will be (h = 6.62×10−34kg.m/s)
View Solution
Q3
A dust particle has mass equal to 10−11g, diameter 10−4cm and velocity 10−4cm/s. The error in measurement of velocity is 0.1%. What will be the uncertainty in its position?
View Solution
Q4
The uncertainty in position and velocity of a particle are 10−10m and 5.27×10−24ms−1 respectively. Calculate the mass of the particle. (h=6.625×10−34J−s).
View Solution
Q5
The uncertainty in position and velocity of the particle are 0.1nm and 5.27×10−24ms−1 respectively then find the mass of the particle (h=6.625×10−34Js−1).