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Question

The uncertainty in the momentum of an eklectron is 10×105kgms1.The uncertainty in its position will be:
(h=6.62×1034kgm2s1)

  1. 1.05×1026
  2. 5.27×1031
  3. 1.05×1028
  4. 5.25×1028

A
1.05×1026
B
1.05×1028
C
5.25×1028
D
5.27×1031
Solution
Verified by Toppr

Uncertainty in momentum ΔP=10×105kgms1
According to Heisenberg uncertainty principle
ΔPΔxh4z
10×105Δx6.626×10344×3.14
Δx6.626×10344×3.14×10×105
Δx0.5275×1030
Δx5.275×1031.

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