The uncertainty in the momentum of an electron is 1.0 $\times$ 10 $^{- 5}$ kg m s $^{- 1}$ . The uncertainty of its position will be:
[h = 6.626 $\times$ 10 $^{- 34}$ kg m $^{2}$ s $^{- 1}$ ]

Question

The uncertainty in the momentum of an electron is 1.0

\times

10

^{- 5}

kg m s

^{- 1}

. The uncertainty of its position will be:

[h = 6.626

\times

10

^{- 34}

kg m

^{2}

s

^{- 1}

]

Toppr Admin · Accepted Answer

Uncertainty in the momentum -10-x2212-6kgms-x2212-1-x394-P-10-x2212-6 kgms-x2212-1-x394-P-x22C5-x394-x-x2265-b4z-x394-x-x2265-h4z-x394-p-x394-x-x2265-6-626-xD7-10-x2212-344-xD7-3-14-xD7-10-x2212-6-x394-x-x2265-5-27-xD7-10-x2212-29mOption C-

The uncertainty in the momentum of an electron is $10^{- 6} k g m s^{- 1}$ . What will be the uncertainty in its position? [ $h = 6.6 \times - 10^{- 34} J s$ ]
$1.65 \times 10^{- 28}$ m
$1.65 \times 10^{- 40}$ m
$5.25 \times 10^{- 29}$ m
$5.25 \times 10^{- 40}$ m

Uncertainty in the momentum $= 10^{- 6}$ kgm $s^{- 1}$
$Δ P = 10^{- 6}$ kgm $s^{- 1}$
$Δ P \cdot Δ x \geq \frac{b}{4 z}$
$Δ x \geq \frac{h}{4 z Δ p}$
$Δ x \geq \frac{6.626 \times 10^{- 34}}{4 \times 3.14 \times 10^{- 6}}$
$Δ x \geq 5.27 \times 10^{- 29} m$
Option C.

The uncertainty in the momentum of an electron is 10−6kgms−1. What will be the uncertainty in its position? [h=6.6×−10−34Js]1.65×10−28m1.65×10−40m5.25×10−29m5.25×10−40m

Uncertainty in the momentum =10−6kgms−1ΔP=10−6 kgms−1ΔP⋅Δx≥b4zΔx≥h4zΔpΔx≥6.626×10−344×3.14×10−6Δx≥5.27×10−29mOption C.

The uncertainty in the momentum of an electron is $10^{- 6} k g m s^{- 1}$ . What will be the uncertainty in its position? [ $h = 6.6 \times - 10^{- 34} J s$ ]
$1.65 \times 10^{- 28}$ m
$1.65 \times 10^{- 40}$ m
$5.25 \times 10^{- 29}$ m
$5.25 \times 10^{- 40}$ m

Uncertainty in the momentum $= 10^{- 6}$ kgm $s^{- 1}$
$Δ P = 10^{- 6}$ kgm $s^{- 1}$
$Δ P \cdot Δ x \geq \frac{b}{4 z}$
$Δ x \geq \frac{h}{4 z Δ p}$
$Δ x \geq \frac{6.626 \times 10^{- 34}}{4 \times 3.14 \times 10^{- 6}}$
$Δ x \geq 5.27 \times 10^{- 29} m$
Option C.