The unit of equilibrium constant K-c- in general is-moles - lit-lits - mole-lit - mol- -Delta n-mole - lit-Delta n-

Question

Toppr Admin · Accepted Answer

The unit of the equilibrium constant Kc is -mole-lit-x394-n-Here- -x394-n is the difference in the total number of gaseous products and total number of gaseous reactants-Hence- option C is correct-

The unit of equilibrium constant $K_{c}$ in general is:
$(m o l e s / l i t)$
$(l i t s / m o l e)$
$(l i t / m o l)^{Δ n}$
$(m o l e / l i t)^{Δ n}$

The unit of the equilibrium constant $K_{c}$ is $(m o l e / l i t)^{Δ n}$ .

Here, $Δ n$ is the difference in the total number of gaseous products and total number of gaseous reactants.

Hence, option C is correct.

The unit of equilibrium constant Kc in general is:(moles/lit)(lits/mole)(lit/mol)Δn(mole/lit)Δn

The unit of the equilibrium constant Kc is (mole/lit)Δn.Here, Δn is the difference in the total number of gaseous products and total number of gaseous reactants.Hence, option C is correct.

The unit of equilibrium constant $K_{c}$ in general is:
$(m o l e s / l i t)$
$(l i t s / m o l e)$
$(l i t / m o l)^{Δ n}$
$(m o l e / l i t)^{Δ n}$

The unit of the equilibrium constant $K_{c}$ is $(m o l e / l i t)^{Δ n}$ .

Here, $Δ n$ is the difference in the total number of gaseous products and total number of gaseous reactants.

Hence, option C is correct.