Question

# The upper half of an inclined plane of inclination θ is perfectly smooth while the lower half rough. A block starting from rest at the top of the plane will again come to rest at the bottom if the coefficient of friction between the block and the lower half of the plane is given by.

A
μ=2tanθ
B
μ=tanθ
C
μ=2/(tanθ)
D
μ=1/tanθ
Solution
Verified by Toppr

#### Suppose length of plane is L. When block descends the plane, rise in kinetic energy = fall in potential energy =mgLsinθiWork done by friction =μ×(reaction)×distance 0+μ(mgcosθ)×(L/2)=μ(mgcosθ)×(L/2)Now, work done= change in KEmgLsinθ=μ(mgcosθ)×(L/2)⇒tanθ=μ/2∴μ=2tanθ.

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