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Question

The value of $1 J = M^{n}$ litre -bar in $n = - 1$ then the value of $M$ is?
$10$
$100$
$10^{- 2}$
$10^{4}$

A

100

B

10

C

10^{- 2}

D

10^{4}

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Solution

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$1$ $L - a t m = 101.33 J$
$∴ 1 J = \frac{1}{101.33} L - a t m$
$1 a t m = 1.0133 b a r$
$∴ 1 J = \frac{1.0133}{101.33} L - b a r = \frac{1}{100} = {(100)}^{- 1}$
$∴ M = 100$

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