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Question

The value of $2 \sqrt{3} + \sqrt{3}$ is equal to
$2 \sqrt{6}$
$3 \sqrt{3}$
$4 \sqrt{6}$
$6$

A

6

B

2 \sqrt{6}

C

3 \sqrt{3}

D

4 \sqrt{6}

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Solution

Verified by Toppr

$2 \sqrt{3} + \sqrt{3} = (2 + 1) \sqrt{3} = 3 \sqrt{3}$

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