Question

The value of $A+B+C$ is

• A. $15$
• B. $16$
• C. $12$
• D. $18$

Answer 1

Answer: (D)

As the right hand digit of the sum of $A+B+C=C,$

it means that $A+B=10$ so $A$ or $B,$ none can be $0.$ Also, the sum of $A+B+C$ can not exceed $19.$

So, $1$ is carried to the second column.
Now, $1+A+B+C$ gives $A$ as the right digit of the sum.

So, $A=C+1.$

Further, again $1$ is carried over to the third column as $A$.

cannot be $0$ and the sum of $1+A+B+C$ can be at most $19$.
On adding $A+B+C+1$ we get BA, thus here $B=1.$
Using $A+B=10,A=10-1=9$
Also, $A=C+1$
$\Rightarrow C=A-1=9-1=8$.
So, $A=9,B=1$ and $C=8$ satisfy all the conditions.

$\therefore A+B+C=9+1+8=18$

So, option B is correct.