Question

The value of A is :

• A. $9$
• B. $6$
• C. $1$
• D. $7$

Answer 1

Answer: (A)

As the right hand digit of the sum of $A+B+C=C,$

it means that $A+B=10$ so $A$ or $B,$ none can be $0.$

Also, the sum of $A+B+C$ can not exceed $19.$

So, $1$ is carried to the second column.
Now, $1+A+B+C$ gives $A$ as the right digit of the sum.

So, $A=C+1.$

Further, again $1$ is carried over to the third column as A

cannot be 0 and the sum of $1+A+B+C$ can be at most 19.
On adding $A+B+C+1$ we get BA, thus here $B=1.$
Using $A+B=10,A=10-1=9$
Also, $A=C+1$
$\Rightarrow C=A-1=9-1=8.$
So, $A=9,B=1$ and $C=8$ satisfy all the conditions.

So, option A is correct.