The value of a machine depreciates the rate of 10- every year- It was purchased 3 years ago- If its present value is 8748- its purchase price was-8-00085-0001-00012-000

Question

Toppr Admin · Accepted Answer

The correct option is D 12-000Machine-apos-s purchase price was-P-1-x2212-R100-w-Rs8748-1-x2212-10100-3-Rs8748-9100-3-Rs8748-xD7-109-xD7-109-xD7-109-Rs12000

The value of a machine depreciates at the rate of $10 %$ every year. It was purchased $3$ years ago. If its present value is $8748$ , its purchase price was.
$8, 000$
$85, 000$
$1, 000$
$12, 000$

The correct option is D $12, 000$
Machine's purchase price was
$= \frac{P}{{(1 - \frac{R}{100})}^{w}} = R s \frac{8748}{{(1 - \frac{10}{100})}^{3}} = R s \frac{8748}{{(\frac{9}{100})}^{3}} = R s 8748 \times \frac{10}{9} \times \frac{10}{9} \times \frac{10}{9} = R s 12000$

The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is 8748, its purchase price was.8,00085,0001,00012,000

The correct option is D 12,000Machine's purchase price was=P(1−R100)w=Rs8748(1−10100)3=Rs8748(9100)3=Rs8748×109×109×109=Rs12000

The value of a machine depreciates at the rate of $10 %$ every year. It was purchased $3$ years ago. If its present value is $8748$ , its purchase price was.
$8, 000$
$85, 000$
$1, 000$
$12, 000$

The correct option is D $12, 000$
Machine's purchase price was
$= \frac{P}{{(1 - \frac{R}{100})}^{w}} = R s \frac{8748}{{(1 - \frac{10}{100})}^{3}} = R s \frac{8748}{{(\frac{9}{100})}^{3}} = R s 8748 \times \frac{10}{9} \times \frac{10}{9} \times \frac{10}{9} = R s 12000$