The value of $g$ (acceleration due to gravity) at earth's surface is $10 m s^{- 2}$ . It's value at the centre of the earth which is assumed to be a sphere of radius $R$ metre and uniform mass density is,

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Answer 1

Net force acting on an object placed at the center of the earth is zero since all the forces act on the object spherical symmetrically and hence cancel out.
Since there is no force at the center of earth, there would be no acceleration.

Answer 2

Net force acting on an object placed at the center of the earth is zero since all the forces act on the object spherical symmetrically and hence cancel out.

Since there is no force at the center of earth, there would be no acceleration.

The value of $g$ (acceleration due to gravity) at earth's surface is $10 m s^{- 2}$ . It's value at the centre of the earth which is assumed to be a sphere of radius $R$ metre and uniform mass density is,

$5$

$\frac{1 0}{R}$

$\frac{1 0}{2 R}$

$z e r o$

Net force acting on an object placed at the center of the earth is zero since all the forces act on the object spherical symmetrically and hence cancel out.
Since there is no force at the center of earth, there would be no acceleration.

The value of acceleration due to gravity on earth is.

How is the acceleration due to gravity on earth surface related to the mass $M$ and radius $R$ of earth?

The mass of earth is $80$ times that of moon and its diameter is double that of moon. If the value of acceleration due to gravity on earth is $9.8$ $m s^{- 2}$ then the value of acceleration due to gravity on moon will be?

If $R$ is the radius of the earth and $g$ the acceleration due to gravity on the earth's surface, then mean density of the earth is:

Value of g is:

The value of g (acceleration due to gravity) at earth's surface is 10ms−2. It's value at the centre of the earth which is assumed to be a sphere of radius R metre and uniform mass density is,

5

R10​

2R10​

zero

Net force acting on an object placed at the center of the earth is zero since all the forces act on the object spherical symmetrically and hence cancel out.Since there is no force at the center of earth, there would be no acceleration.

The value of acceleration due to gravity on earth is.

How is the acceleration due to gravity on earth surface related to the mass M and radius R of earth?

The mass of earth is 80 times that of moon and its diameter is double that of moon. If the value of acceleration due to gravity on earth is 9.8 ms−2 then the value of acceleration due to gravity on moon will be?

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, then mean density of the earth is:

Value of g is:

The value of $g$ (acceleration due to gravity) at earth's surface is $10 m s^{- 2}$ . It's value at the centre of the earth which is assumed to be a sphere of radius $R$ metre and uniform mass density is,

$5$

$\frac{1 0}{R}$

$\frac{1 0}{2 R}$

$z e r o$

Net force acting on an object placed at the center of the earth is zero since all the forces act on the object spherical symmetrically and hence cancel out.
Since there is no force at the center of earth, there would be no acceleration.

How is the acceleration due to gravity on earth surface related to the mass $M$ and radius $R$ of earth?

The mass of earth is $80$ times that of moon and its diameter is double that of moon. If the value of acceleration due to gravity on earth is $9.8$ $m s^{- 2}$ then the value of acceleration due to gravity on moon will be?

If $R$ is the radius of the earth and $g$ the acceleration due to gravity on the earth's surface, then mean density of the earth is: