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Updated on : 2022-09-05

Solution

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Correct option is B)

$g_{_{′}}=g−ω_{2}R$

So the weight at the equator is $mg_{_{′}}=m(g−ω_{2}R)$

Gravity above the earth's surface is given by

$g_{′}=g(1−R2h )$

Implies the weight at the equator above the earth's surface is $mg_{_{′}}=mg(1−R2h )$

It is given that these two weights are equal,

$⇒m(g−ω_{2}R)=mg(1−R2h )$

$⇒g−ω_{2}R=g−R2gh $

$⇒ω_{2}R=R2gh $

$⇒h=2gω_{2}R_{2} $

Solve any question of Gravitation with:-

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