The value of left-dfrac 25 right-2- is

Question

Toppr Admin · Accepted Answer

Correct option is C- -dfrac -25-4-We will use- law of exponent -a-m-dfrac -1-a-m- where -a- non-zero integer-left-dfrac -2-5-right-2-dfrac -1-left-dfrac -2-5-right-2- -dfrac -1-dfrac -4-25-dfrac -25-4-

The value of $$\left(\dfrac 25 \right)^{-2}$$ is

Correct option is C. $$\dfrac {25}{4}$$
We will use, law of exponent $$a^{-m}=\dfrac {1}{a^m}$$ where $$a=$$ non-zero integer

$$\left(\dfrac {2}{5}\right)^{-2}=\dfrac {1}{\left(\dfrac {2}{5}\right)^2} \\=\dfrac {1}{\dfrac {4}{25}}\\=\dfrac {25}{4}$$

The value of $$\left(\dfrac 25 \right)^{-2}$$ is

Correct option is C. $$\dfrac {25}{4}$$We will use, law of exponent $$a^{-m}=\dfrac {1}{a^m}$$ where $$a=$$ non-zero integer$$\left(\dfrac {2}{5}\right)^{-2}=\dfrac {1}{\left(\dfrac {2}{5}\right)^2} \\=\dfrac {1}{\dfrac {4}{25}}\\=\dfrac {25}{4}$$

Correct option is C. $$\dfrac {25}{4}$$
We will use, law of exponent $$a^{-m}=\dfrac {1}{a^m}$$ where $$a=$$ non-zero integer

$$\left(\dfrac {2}{5}\right)^{-2}=\dfrac {1}{\left(\dfrac {2}{5}\right)^2} \\=\dfrac {1}{\dfrac {4}{25}}\\=\dfrac {25}{4}$$