The value of the resistor- R-S- needed in the DC voltage regulator circuit shown here- equalsdfrac-V-i-V-L-n-1-I-L-dfrac-V-i-V-L-n I-L-dfrac-V-i-V-L-n-1-I-L-dfrac-V-i-V-L-n I-L-

Question

Toppr Admin · Accepted Answer

Total current in resistance RSI-nIL-IL-n-1-ILVoltage across RS is VS-Vi-x2212-VL

The value of the resistor, $R_{S}$ , needed in the DC voltage regulator circuit shown here, equals

$\frac{(V_{i} + V_{L})}{(n + 1) I_{L}}$
$\frac{(V_{i} + V_{L})}{n I_{L}}$
$\frac{(V_{i} - V_{L})}{(n + 1) I_{L}}$
$\frac{(V_{i} - V_{L})}{n I_{L}}$

Total current in resistance $R_{S}$ $I = n I_{L} + I_{L} = (n + 1) I_{L}$
Voltage across $R_{S}$ is $V_{S} = V_{i} - V_{L}$

The value of the resistor, RS, needed in the DC voltage regulator circuit shown here, equals(Vi+VL)(n+1)IL(Vi+VL)nIL(Vi−VL)(n+1)IL(Vi−VL)nIL

Total current in resistance RSI=nIL+IL=(n+1)ILVoltage across RS is VS=Vi−VL

The value of the resistor, $R_{S}$ , needed in the DC voltage regulator circuit shown here, equals

$\frac{(V_{i} + V_{L})}{(n + 1) I_{L}}$
$\frac{(V_{i} + V_{L})}{n I_{L}}$
$\frac{(V_{i} - V_{L})}{(n + 1) I_{L}}$
$\frac{(V_{i} - V_{L})}{n I_{L}}$

Total current in resistance $R_{S}$ $I = n I_{L} + I_{L} = (n + 1) I_{L}$
Voltage across $R_{S}$ is $V_{S} = V_{i} - V_{L}$