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Question

The value of x satisfying the equation 2[3112]+ [x2910]= [5x601]+ [0513]are
  1. 1,2
  2. 2,3
  3. ±2
  4. ±3

A
1,2
B
±2
C
2,3
D
±3
Solution
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The correct option is B 2,3
By comparing, we have
6+x2=5x or x25x+6=0
or (x2)(x3)=0
x=2,3

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