The value of- cos-2-30-circ-sin-2-30-circ- is cos 60-o or dfrac-1-2- Enter 1 true or 0 otherwise-

Question

Toppr Admin · Accepted Answer

To prove- cos230-x2218-x2212-sin230-x2218-cos60-x2218-L-H-S- cos230-x2218-x2212-sin230-x2218- -x221A-32-2-x2212-12-2- 34-x2212-14- 24- 12- cos60-x2218-Thus- L-H-S-R-H-S

The value of: ${cos}^{2} 30^{\circ} - {sin}^{2} 30^{\circ}$ is $cos 60^{o}$ or $\frac{1}{2}$ .( Enter 1 if true or 0 otherwise)

To prove: ${cos}^{2} 30^{\circ} - {sin}^{2} 30^{\circ} = cos 60^{\circ}$

L.H.S: ${cos}^{2} 30^{\circ} - {sin}^{2} 30^{\circ}$
= $(\frac{\sqrt{3}}{2})^{2} - (\frac{1}{2})^{2}$

= $\frac{3}{4} - \frac{1}{4}$

= $\frac{2}{4}$

= $\frac{1}{2}$
= $cos 60^{\circ}$
Thus, $L . H . S . = R . H . S$

The value of: cos230∘−sin230∘ is cos60o or 12.( Enter 1 if true or 0 otherwise)

To prove: cos230∘−sin230∘=cos60∘L.H.S: cos230∘−sin230∘= (√32)2−(12)2= 34−14= 24= 12= cos60∘Thus, L.H.S.=R.H.S

The value of: ${cos}^{2} 30^{\circ} - {sin}^{2} 30^{\circ}$ is $cos 60^{o}$ or $\frac{1}{2}$ .( Enter 1 if true or 0 otherwise)

To prove: ${cos}^{2} 30^{\circ} - {sin}^{2} 30^{\circ} = cos 60^{\circ}$

L.H.S: ${cos}^{2} 30^{\circ} - {sin}^{2} 30^{\circ}$
= $(\frac{\sqrt{3}}{2})^{2} - (\frac{1}{2})^{2}$

= $\frac{3}{4} - \frac{1}{4}$

= $\frac{2}{4}$

= $\frac{1}{2}$
= $cos 60^{\circ}$
Thus, $L . H . S . = R . H . S$