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Question

The value of $\frac{1}{97} + \frac{2}{97} + . . . . . + \frac{96}{97}$ is:
$48$
None of the above
$1$
$- 48$

A

- 48

B

None of the above

C

48

D

1

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Solution

Verified by Toppr

We know,
Sum of $n$ natural numbers $= \frac{n (n + 1)}{2}$
$∴ \frac{1}{97} + \frac{2}{97} + . . . . . + \frac{96}{97}$

$= \frac{1 + 2 + 3 + . . . . + 96}{97}$

$= \frac{96 \times 97}{2 \times 97}$

$= 48$
Hence, the answer is $48$ .

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