Question

The variation of acceleration due to gravity $g$ with distance $d$ from centre of the earth is best represented by (R=Earth's radius) :

• A.
  
• B.
  
• C.
  
• D.
  

Answer 1

With depth

$g_1=g(1-\frac{\left(d\right)}{R})$

As depth $d$ goes on increasing $g_1$ goes on decreasing, it remains maximum at the surface of Earth .The above equation is in the form of straight line.

With height

$g_2=g(1-\frac{2h}{R})$

$=g-\frac{2gh}{R}$

$g_2\propto \frac{1}{R}$ (Hyperbola)

Acceleration due to gravity goes on decreasing as the $h$ above Earth surface increases.

Hence the correct answer is option A.