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Question

The velocity of a particle varies with distance x from a fixed origin as $$v=Ax+\dfrac { { Bx }^{ 2 } }{ C+x } $$, where A,B and C are dimensional constant then the dimensional formula of $$\dfrac { AB }{ C } $$ is

A
$$\left[ ML{ T }^{ -2 } \right] $$
B
$$\left[ M^{ 0 }L^{ -1 }{ T }^{ -2 } \right] $$
C
$$\left[ M^{ 0 }L^{ 0 }{ T }^{ -2 } \right] $$
D
$$\left[ ML^{ -1 }{ T }^{ -2 } \right] $$
Solution
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Correct option is A. $$\left[ ML{ T }^{ -2 } \right] $$

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