The velocity-time graph of a body is shown in figure.

The ratio of the average velocities during the intervals $O A$ and $A B$ is 1.
The ratio of the $\frac{O A}{O B}$ during the intervals $O A$ and $A B$ is $\frac{1}{4}$ .
The ratio of the distance coveredduring the intervals $O A$ and $A B$ is $\frac{1}{2}$ .;
The ratio of the average accelerationsduring the intervals $O A$ and $A B$ is same as distance covered.

Question

The velocity-time graph of a body is shown in figure.

The ratio of the average velocities during the intervals $O A$ and $A B$ is 1.
The ratio of the $\frac{O A}{O B}$ during the intervals $O A$ and $A B$ is $\frac{1}{4}$ .
The ratio of the distance coveredduring the intervals $O A$ and $A B$ is $\frac{1}{2}$ .;
The ratio of the average accelerationsduring the intervals $O A$ and $A B$ is same as distance covered.

Toppr Admin · Accepted Answer

From t-0 to t-A velocity increases from 0 to v where v is the velocity at t-AFrom t-A to t-B velocity increases from v to 0 where v is the velocity at t-AHence- vavg during interval-xA0- 0 to A is same as vavg during interval-xA0- A to B

From t=0 to t=A velocity increases from 0 to v where v is the velocity at t=AFrom t=A to t=B velocity increases from v to 0 where v is the velocity at t=AHence, vavg during interval 0 to A is same as vavg during interval A to B

From $t = 0$ to $t = A$ velocity increases from 0 to v where v is the velocity at $t = A$
From $t = A$ to $t = B$ velocity increases from v to 0 where v is the velocity at $t = A$
Hence, $v_{a v g}$ during interval 0 to A is same as $v_{a v g}$ during interval A to B