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Question

The vertical height of a conical tent is $$42$$ dm and its diameter of the base is $$54$$ dm. How many persons can it accommodate, if each person is to be allowed $$2916$$ $$\displaystyle \ \text{dm}^{3}$$ of space ? $$\displaystyle \left ( \pi =22/7 \right )$$

Solution
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Volume of the cone i.e capacity of the cone
$$\displaystyle =\frac{1}{3}\pi r^{2}h$$
$$\displaystyle =\frac{1}{3}\times \frac{22}{7}\times 27\times 27\times 42dm^{3}$$
$$\displaystyle =32076\>dm^{3}$$
$$\displaystyle \therefore $$ No.of person$$\displaystyle =\frac{32076}{2916}=11$$

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