The voltage - current -V-I- graph of a metallic conductor two different temperature T-1- and T-2- is shown below- At which temperature is the resistance higher-

Question

Toppr Admin · Accepted Answer

The mathematical expression for Ohm-apos-s law is-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-V-IRThus- graph between V versus I gives a straight line with slope R-Since- slope at-xA0-T2 is more than slope at-xA0-T1-xA0-For metallic conductors- resistance is directly proportional to temperature- Thus- resistance is higher at-xA0-T2

The voltage - current $(V - I)$ graph of a metallic conductor at two different temperature $T_{1}$ and $T_{2}$ is shown below. At which temperature is the resistance higher?

The mathematical expression for Ohm's law is:
$V = I R$
Thus, graph between V versus I gives a straight line with slope R.
Since, slope at $T_{2}$ is more than slope at $T_{1}$ .
For metallic conductors, resistance is directly proportional to temperature. Thus, resistance is higher at $T_{2}$

The voltage - current (V−I) graph of a metallic conductor at two different temperature T1 and T2 is shown below. At which temperature is the resistance higher?

The mathematical expression for Ohm's law is: V=IRThus, graph between V versus I gives a straight line with slope R.Since, slope at T2 is more than slope at T1. For metallic conductors, resistance is directly proportional to temperature. Thus, resistance is higher at T2

The voltage - current $(V - I)$ graph of a metallic conductor at two different temperature $T_{1}$ and $T_{2}$ is shown below. At which temperature is the resistance higher?

The mathematical expression for Ohm's law is:
$V = I R$
Thus, graph between V versus I gives a straight line with slope R.
Since, slope at $T_{2}$ is more than slope at $T_{1}$ .
For metallic conductors, resistance is directly proportional to temperature. Thus, resistance is higher at $T_{2}$