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The peak value of the triangular wave is $V_{0}$.

The equation of the line in the interval $0$ to $4Tβ$ is given as,

$V=T4V_{0}βt$

The rms value of the triangular wave is given as,

$V_{rms}=T4ββ«_{0}(V)_{2}dtβ$

$=T4βΓ(T4V_{0}β)_{2}β«_{0}(t)_{2}dtβ$

$=(T_{3}64V_{0}_{2}β)(3t_{3}β)_{0}β$

$=3βV_{0}β$

Thus the rms value of $V$ in the time interval $0$ to $4Tβ$ is $3βV_{0}β$.

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