The volume occupied by 3-5 g of O-2 gas 27-o C - 760 mm pressure is-Molecular weight of oxygen -16 g-mole-3-5 litres5-24 litres2-45 litres6-4 litres

Question

The volume occupied by 3-5 g of O-2 gas 27-o C - 760  mm pressure is-Molecular weight of oxygen -16 g-mole-3-5 litres5-24 litres2-45 litres6-4 litres

Toppr Admin · Accepted Answer

As we know- one mole of a gaseous substance occupies 22-4 litres-xA0-So- 32 g of oxygen occupies 22-4 litres-xA0-x2234- 3-5 g of oxygen occupies 3-5-xD7-22-432-2-45 litresHence- the correct answer is option A-

The volume occupied by $3.5$ g of $O_{2}$ gas at $27^{o} C$ & $760$ mm pressure is:

[Molecular weight of oxygen $= 16$ g/mole]

$3.5$ litres
$5.24$ litres
$2.45$ litres
$6.4$ litres

As we know, one mole of a gaseous substance occupies $22.4$ litres

So, $32$ g of oxygen occupies $22.4$ litres

$∴$ $3.5$ g of oxygen occupies $3.5 \times \frac{22.4}{32} = 2.45$ litres

Hence, the correct answer is option $A$ .

The volume occupied by 3.5 g of O2 gas at 27oC & 760 mm pressure is:[Molecular weight of oxygen =16 g/mole]3.5 litres5.24 litres2.45 litres6.4 litres

As we know, one mole of a gaseous substance occupies 22.4 litres So, 32 g of oxygen occupies 22.4 litres ∴ 3.5 g of oxygen occupies 3.5×22.432=2.45 litresHence, the correct answer is option A.

The volume occupied by $3.5$ g of $O_{2}$ gas at $27^{o} C$ & $760$ mm pressure is:

[Molecular weight of oxygen $= 16$ g/mole]

$3.5$ litres
$5.24$ litres
$2.45$ litres
$6.4$ litres

As we know, one mole of a gaseous substance occupies $22.4$ litres

So, $32$ g of oxygen occupies $22.4$ litres

$∴$ $3.5$ g of oxygen occupies $3.5 \times \frac{22.4}{32} = 2.45$ litres

Hence, the correct answer is option $A$ .