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The volume of a cylindrical oil can is $3080$ cm $^{3}$ . If the base radius is $10.5$ cm, find the height of the can. $(π = 3.142)$
$8.89 c m$
$6.89 c m$
$4.89 c m$
None of these

A

6.89 c m

B

8.89 c m

C

4.89 c m

D

None of these

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Solution

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$V = π r^{2} h = 3080 c m^{3}$ & $r = 10.5 c m$
$\Rightarrow h = \frac{3080}{π (10.5) 2} = 8.89 c m$

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