The volume of a right circular cone is 9856 cm-3- If the diameter of the base is 28 cm- findslant height of the cone

Question

Toppr Admin · Accepted Answer

Volume of cone -13-x3C0-r2h-x21D2-9856-x3C0-6-14-2h-x21D2-h-9856-xD7-3-xD7-714-xD7-14-xD7-22-48cmBy Pythagoras theorem- l2-h2-r2-x21D2-l-x221A-482-142-x221A-2304-196-x221A-2500-50cm-

The volume of a right circular cone is $9856 c m^{3}$ . If the diameter of the base is $28 c m$ . find
slant height of the cone

Volume of cone $= \frac{1}{3} π r^{2} h$
$\Rightarrow 9856 = \frac{π}{6} (14)^{2} h$
$\Rightarrow h = \frac{9856 \times 3 \times 7}{14 \times 14 \times 22} = 48$ cm
By Pythagoras theorem, $l^{2} = h^{2} + r^{2}$
$\Rightarrow l = \sqrt{48^{2} + 14^{2}} = \sqrt{2304 + 196} = \sqrt{2500} = 50$ cm.

The volume of a right circular cone is 9856 cm3. If the diameter of the base is 28 cm. findslant height of the cone

Volume of cone =13πr2h⇒9856=π6(14)2h⇒h=9856×3×714×14×22=48cmBy Pythagoras theorem, l2=h2+r2⇒l=√482+142=√2304+196=√2500=50cm.

The volume of a right circular cone is $9856 c m^{3}$ . If the diameter of the base is $28 c m$ . find
slant height of the cone

Volume of cone $= \frac{1}{3} π r^{2} h$
$\Rightarrow 9856 = \frac{π}{6} (14)^{2} h$
$\Rightarrow h = \frac{9856 \times 3 \times 7}{14 \times 14 \times 22} = 48$ cm
By Pythagoras theorem, $l^{2} = h^{2} + r^{2}$
$\Rightarrow l = \sqrt{48^{2} + 14^{2}} = \sqrt{2304 + 196} = \sqrt{2500} = 50$ cm.