The volume-V- of a monatomic gas varies with its temperature -T- as shown in the graph- The ratio of work done by the gas- to the heat absorbed by it- when it undergoes a change from state A to state B- is-displaystylefrac-1-3-displaystylefrac-2-5-displaystylefrac-2-3-displaystylefrac-2-7-

Question

Toppr Admin · Accepted Answer

Work-xA0-doneheat-xA0-absorbed-nCp-x394-T-x2212-nCv-x394-TnCp-x394-T-1-x2212-1-x3B3-25

The volume(V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is?

$\frac{1}{3}$
$\frac{2}{5}$
$\frac{2}{3}$
$\frac{2}{7}$

$\frac{w o r k d o n e}{h e a t a b s o r b e d} = \frac{n C_{p} Δ T - n C_{v} Δ T}{n C_{p} Δ T} = 1 - \frac{1}{γ} = \frac{2}{5}$

The volume(V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is?13252327

work doneheat absorbed=nCpΔT−nCvΔTnCpΔT=1−1γ=25

The volume(V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is?

$\frac{1}{3}$
$\frac{2}{5}$
$\frac{2}{3}$
$\frac{2}{7}$

$\frac{w o r k d o n e}{h e a t a b s o r b e d} = \frac{n C_{p} Δ T - n C_{v} Δ T}{n C_{p} Δ T} = 1 - \frac{1}{γ} = \frac{2}{5}$