Question

The weight of $350mL$ of a diatomic gas at $0^{o}C$ and $2$ atm pressure is $1g$. The weight of one atom is:

Answer 1

From Ideal gas equation- $PV=nRT$

Here,

$P=2atm$, $V=350ml=0.35l$

$R=0.0821latm/kmol$ and $T=0^{o}C=273K$

Now, $n=\frac{PV}{RT}$

$n=\frac{2\times 0.35}{0.0821\times 273}$

$n=0.0312mol$

Now, the weight of 0.0312 mol of gas is 1 gram

Therefore, the weight of 1mol of gas would be$=\frac{1}{0.0312}=32g/mol$

Since the gas is diatomic therefore weight of 1 mole atom$=16g/mol$