Question

The weight of three packets are $$2 \dfrac{3}{4} kg $$. $$3 \dfrac{1}{3} kg. $$ and $$5\dfrac{2}{5} kg.$$ Find total weight of all the three packets.

Answer 1

Weigth of 1st packet $$= 2\dfrac{3}{4}$$
Weigth of 2nd packet $$= 3\dfrac{1}{3}$$
Weigth of 3rd packet $$= 5\dfrac{2}{5}$$
$$\therefore $$ Total weight
$$= 2\dfrac{3}{4} + 3\dfrac{1}{3} + 5\dfrac{2}{5} = \dfrac{11}{4} + \dfrac{10}{3} + \dfrac{27}{5}$$
$$\left(\because L.C.M \, 4,3,5 = 60 \right)$$
$$= \dfrac{11 \times 15 + 10 \times 20 + 27 \times 12}{60}$$
$$=\dfrac{165 + 200 + 324}{60}$$
$$= \dfrac{689}{60} = 11\dfrac{29}{60}kg$$