The work done by the force →F=A(y2^i+2x2^j), where A is a constant and x & y are in meters around the path shown is :
Ad
zero
Ad2
Ad3
A
Ad2
B
Ad3
C
zero
D
Ad
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Solution
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Variable force is apllied across the path OA to AB to BC to CO
W=∫¯F.d¯r
=∫A(y2¯i+2x2¯j).(dx¯i+dy.¯j)
=∫A(y2dx+2x2dy)
Now following the path of displacement along OA the y=0
WOA=∫x=dx=0A(0+2x2.0)=0+0=0
Similerly, for WAB,x=d
WAB=A[0+2d2d]=2Ad3
Similarly, for WBC,x=d,y=d
WBC=∫x=0x=dA(d2dx+0)
WBC=A[d2(−d)+0]=−Ad3
WCO=A[0+0]
W=0+2Ad3−Ad3+0=Ad3
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