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Question

The work done by the force F=A(y2^i+2x2^j), where A is a constant and x & y are in meters around the path shown is :
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  1. Ad
  2. zero
  3. Ad2
  4. Ad3

A
Ad2
B
Ad3
C
zero
D
Ad
Solution
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Variable force is apllied across the path OA to AB to BC to CO

W=¯F.d¯r

=A(y2¯i+2x2¯j).(dx¯i+dy.¯j)

=A(y2dx+2x2dy)

Now following the path of displacement along OA the y=0

WOA=x=dx=0A(0+2x2.0)=0+0=0

Similerly, for WAB,x=d

WAB=A[0+2d2d]=2Ad3

Similarly, for WBC, x=d,y=d

WBC=x=0x=dA(d2dx+0)

WBC=A[d2(d)+0]=Ad3

WCO=A[0+0]

W=0+2Ad3Ad3+0=Ad3

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