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Updated on : 2022-09-05

Solution

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Correct option is D)

$W=∫Fˉ.drˉ$

$=∫A(y_{2}iˉ+2x_{2}jˉ ).(dxiˉ+dy.jˉ )$

$=∫A(y_{2}dx+2x_{2}dy)$

Now following the path of displacement along $OA$ the $y=0$

$W_{OA}=∫_{x=0}A(0+2x_{2}.0)=0+0=0$

Similerly, for $W_{AB},x=d$

$W_{AB}=A[0+2d_{2}d]=2Ad_{3}$

Similarly, for $W_{BC},x=d,y=d$

$W_{BC}=∫_{x=d}A(d_{2}dx+0)$

$W_{BC}=A[d_{2}(−d)+0]=−Ad_{3}$

$W_{CO}=A[0+0]$

$W=0+2Ad_{3}−Ad_{3}+0=Ad_{3}$

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