The work done in sliding a wooden box of mass $5 k g$ along a friction less inclined plane of inclination $30^{o}$ and length $10 m$ is______ $J$ . $(g = 10 {m s}^{- 2})$

Question

The work done in sliding a wooden box of mass 5 kg along a friction inclined plane of inclination -30-o- and length 10 m is-J- -g-10 -ms-2-1500500250125

Toppr Admin · Accepted Answer

Work done-force-xD7-distanceW-mgsin30-xB0-xD7-lW-50-xD7-12-xD7-10-250J

The work done in sliding a wooden box of mass $5 k g$ along a friction less inclined plane of inclination $30^{o}$ and length $10 m$ is______ $J$ . $(g = 10 {m s}^{- 2})$
$1500$
$500$
$250$
$125$

Work done=force×distance
W=mg $s i n 30 ° \times l$
W= $50 \times \frac{1}{2} \times 10 = 250 J$

The work done in sliding a wooden box of mass 5 kg along a friction less inclined plane of inclination 30o and length 10 m is______J. (g=10 ms−2)1500500250125

Work done=force×distanceW=mgsin30°×lW=50×12×10=250J

The work done in sliding a wooden box of mass $5 k g$ along a friction less inclined plane of inclination $30^{o}$ and length $10 m$ is______ $J$ . $(g = 10 {m s}^{- 2})$
$1500$
$500$
$250$
$125$

Work done=force×distance
W=mg $s i n 30 ° \times l$
W= $50 \times \frac{1}{2} \times 10 = 250 J$