0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The work done to raise a mass m from the surface of the earth to a height h, which is equal to the radius of the earth, is :

A
2 mgR
B
$$\dfrac{1}{2} mgR$$
C
mgR
D
$$\dfrac{3}{2} mg R$$
Solution
Verified by Toppr

Correct option is C. $$\dfrac{1}{2} mgR$$
Initial potential energy at earths surface is
$$U_i = \dfrac{-GMm}{R}$$
Final potential energy at height h = R
$$U_f = \dfrac{-GMm}{2R}$$
As work done = change in PE
$$\therefore W = U_f - U_i$$
$$= \dfrac{GMm}{2R} $$
$$(\because GM = gR^2)$$
$$= \dfrac{gR^2m}{2R} = \dfrac{mgR}{2}$$

Was this answer helpful?
49
Similar Questions
Q1
The work done to raise a mass m from the surface of the earth to a height h which is equal to the radius of the earth
View Solution
Q2
The work done to raise a mass m from the surface of the earth to a height h, which is equal to the radius of the earth is
View Solution
Q3
The amount of work done in lifting a body of mass 'm' from the surface of the earth to a height equal to twice the radius of the earth is
View Solution
Q4
The amount of work done in slowly lifting a body of mass 'm' from the surface of the earth to height equal to half the radius of the earth is
View Solution
Q5
Find the work done to take a particle of mass m from surface of the earth to a height equal to 2R.
View Solution