The work function of a metal is 2.5 eV. The maximum kinetic energy of the photoelectrons emitted if a radiation of wavelength 3000Ao falls on it is :
(h=6.63×10−34 Js and c=3×108 m/s)
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Maximum kinetic energy, K.E.max=hcλ−ϕ
So, the answer is option (D).
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A photon of wavelength 4 × 10–7 m strikes on metal surface, the work function of the metal being 2.13 eV. Calculate (i) the energy of the photon (eV),
(ii) the kinetic energy of the emission, and
(iii) the velocity of the photoelectron (1 eV= 1.6020 × 10–19 J).
If the work function for a certain metal is 3.2×10−19joule and it is illuminated with light of frequency 8×1014Hz. The maximum kinetic energy of the photo-electrons would be (h=6.63×10−34Js
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