The work function of a metal is 2.5 eV. The maximum kinetic energy of the photoelectrons emitted if a radiation of wavelength 3000Ao falls on it is :
(h=6.63×10−34 Js and c=3×108 m/s)
A
1.12×10−19J
B
4.8×10−19J
C
3.2×10−19J
D
2.63×10−19J
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Solution
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Maximum kinetic energy, K.E.max=hcλ−ϕ
=6.63×10−34×3×1083000×10−10−2.5×1.6×10−19
=(6.63×10−19−4×10−19)J
=2.63×10−19J.
So, the answer is option (D).
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