The work function of the metal, if the kinetic energies of the photoelectrons are $$E_{1}$$ and $$E_{2}$$, with wavelengths of incident light $$\lambda_{1}$$ and $$\lambda_{2}$$, is
A
$$\dfrac {E_{1}E_{2}}{\lambda_{2} - \lambda_{1}}$$
B
$$\dfrac {\lambda_{1}\lambda_{2}E_{1}}{(\lambda_{1} - \lambda_{2})E_{2}}$$
C
$$\dfrac {E_{1}\lambda_{1} - E_{2}\lambda_{2}}{\lambda_{2} - \lambda_{1}}$$
D
$$\dfrac {(E_{1} - E_{2})\lambda_{1}\lambda_{2}}{(\lambda_{1} - \lambda_{2})}$$
Correct option is A. $$\dfrac {E_{1}\lambda_{1} - E_{2}\lambda_{2}}{\lambda_{2} - \lambda_{1}}$$