The x and y coordinates of the particle at any time are x=5t−2t2 and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is:

0

5m/s2

−4m/s2

−8m/s2

A

5m/s2

B

−4m/s2

C

0

D

−8m/s2

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Solution

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x=5t−2t2 y=10t dxdt=5−4t ax=d2xdt2=−4

ay=d2ydt2=0

a=ax+ay=−4+0

a=−4ms2

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