The x and y coordinates of the particle at any time are x=5t−2t2 and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is:
0
5m/s2
−4m/s2
−8m/s2
A
5m/s2
B
−8m/s2
C
0
D
−4m/s2
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Solution
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x=5t−2t2 y=10t dxdt=5−4t ax=d2xdt2=−4
ay=d2ydt2=0
a=ax+ay=−4+0
a=−4ms2
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