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Standard XII
Physics
Question
The
x
−
t
graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at
t
=
4
3
s
is
π
2
32
c
m
/
s
2
−
π
2
32
c
m
/
s
2
√
3
32
π
2
c
m
/
s
2
−
√
3
32
π
2
c
m
/
s
2
A
π
2
32
c
m
/
s
2
B
−
√
3
32
π
2
c
m
/
s
2
C
√
3
32
π
2
c
m
/
s
2
D
−
π
2
32
c
m
/
s
2
Open in App
Solution
Verified by Toppr
The given motion is represented by
x
=
1
sin
(
π
/
4
)
t
d
2
x
d
t
2
=
−
π
2
16
sin
(
π
/
4
)
t
At
t
=
4
/
3
s
e
c
,
d
2
x
d
t
2
=
−
√
3
32
π
2
c
m
/
s
2
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