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Question

Then which of the following is true?
$75^{o}$
$A P ⊥ A B$
$O M = r$
$∠ A M O = 45^{o}$

A

∠ A M O = 45^{o}

B

P M ⊥ A B

C

A P ⊥ A B

D

O M = r

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Solution

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A perpendicular line drawn from centre of the circle to a chord bisects the chord perpendicularly.
$∴ O M ⊥ A B$
Also, Centre mid of the chord and mid point of the arc lie on the same line.
$∴ O P ⊥ A B$
$=> P M ⊥ A B$

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