Question

There are $10$ condensers each of capacity $5\mu F$. The ratio of minimum to maximum capacity obtained from these condensers will be :

• A. $1:50$
• B. $1:100$
• C. $100:1$
• D. $50:1$

Answer 1

Answer: (B)

$C=5\mu F$
minimum capacity is obtained when all are in a series,
$\therefore \frac{1}{c_s}=\frac{1}{c_1}+\frac{1}{c_2}.....+\frac{1}{c_{10}}$
$\frac{1}{c_s}=\frac{1}{5}+\frac{1}{5}+.....+\frac{1}{5}=\frac{10}{5}$
$\therefore c_s=\frac{1}{2}$
maximum capacity is obtained when they are parallety connected
$\therefore c_{eff}=c_1+c_2+.......+c_{10}$
= 5 + 5 + ......+5
$c_p=10\left(5\right)$
$c_p=50$
$\therefore$ Ratio of min to max capacity,
$\frac{c_s}{c_p}=\frac{0.5}{50}=1:100$