There are 27 drops of a conducting fluid. each drop has radius r and each of them is charged to same potential V1 they are then combined to form a bigger drop. the potential of the bigger drop is V2 find the ratio V2/V1 ignore the change in density of fluid on combining the drops.
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let q be the charge on each drop : V1=rkq Let R be radius of single drop. then 34πR3=2734πr3⇒R=3r V2=Rk(27q)=3rk27q=9V1⇒V1V2=9