Question

There are two cuboid boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?

Answer 1

Given

Length of cuboid box(l)$=60$cm

Breadth of cuboid box(b)$=40$cm

Height of cuboid box(h)$=50$cm

Total surface area of cuboidal box $=2(lb+bh+hl)$

$=2(60\times 40+40\times 50+50\times 60)$

$=2(2400+2000+3000)$

$=2\times 7400$

$=14,800c{m}^2$

Total surface area of cuboidal box$=$Rs. $14,800c{m}^2$

(b) Side of cube$\left(a\right)=50$cm

Total surface area of a cube$=6.a^2$

$=6\times {50}^2$

$=6\times 2500$

$=1500m^2$

Total surface area of a cube$=1500c{m}^2$

$\therefore$ Hence cuboidal box requires the lesser amount of material to make.