There is a uniformly charged disc of radius \$R\sqrt { 3 } \$ and surface charge density \$\sigma \$ work done by electric field to brought a charge \$\varrho \$ From centre of disc to distance R along its axis will be :-

\$\dfrac { \sigma QR }{ 2{ \epsilon }_{ \sigma } } \left( \sqrt { 3 } -1 \right) \$

\$\dfrac { \sigma QR\left( \sqrt { 3 } -1) \right) }{ 2{ \epsilon }_{ \sigma } } \$

\$\dfrac { \sigma QR }{ 2{ \epsilon }_{ \sigma } } \left( \sqrt { 2 } -1) \right) \$

\$\dfrac { \sigma QR }{ { \epsilon }_{ \sigma } } \$

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There is a uniformly charged disc of radius $R 3$ and surface charge density $σ$ work done by electric field to brought a charge $ϱ$ From centre of disc to distance R along its axis will be :-

$\frac{σ Q R ( 3 - 1 ) )}{2 ϵ _{σ}}$

$\frac{σ Q R}{2 ϵ _{σ}} (2 - 1))$

$\frac{σ Q R}{2 ϵ _{σ}} (3 - 1)$

$\frac{σ Q R}{ϵ _{σ}}$

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The electric field due to a uniformly charged disc at a point very distant from the surface of the disc is given by
[ $σ$ is the surface charge density on the disc]

Medium

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Find the electric field on the axis of a uniformly charged disc.

Hard

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The surface charge density of a thin charged disc of radius $R$ is $σ$ . The value of the electric field at the centre of the disc is $\frac{σ}{2 ϵ _{0}}$ . With respect to the field at the centre, the electric field along the axis at a distance $R$ from the centre of the disc.

Hard

BITSAT

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An annular disc has inner and outer radius R $_{1}$ and R $_{2}$ respectively. Charge is uniformly distributed. Surface charge density is $σ$ . Find the electric field at any point distant y along the axis of the disc.

Hard

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A very thin disc is uniformly charged with surface charge density $σ > 0$ . Then the electric field intensity on the axis at the point from which the disc is seen at an solid angle $Ω$ is

Medium

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There is a uniformly charged disc of radius R3​ and surface charge density σ work done by electric field to brought a charge ϱ From centre of disc to distance R along its axis will be :-

2ϵσ​σQR(3​−1))​

2ϵσ​σQR​(2​−1))

2ϵσ​σQR​(3​−1)

ϵσ​σQR​

The electric field due to a uniformly charged disc at a point very distant from the surface of the disc is given by [σ is the surface charge density on the disc]

Find the electric field on the axis of a uniformly charged disc.

The surface charge density of a thin charged disc of radius R is σ. The value of the electric field at the centre of the disc is 2ϵ0​σ​. With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc.

An annular disc has inner and outer radius R1​ and R2​ respectively. Charge is uniformly distributed. Surface charge density is σ. Find the electric field at any point distant y along the axis of the disc.

A very thin disc is uniformly charged with surface charge density σ>0. Then the electric field intensity on the axis at the point from which the disc is seen at an solid angle Ω is

There is a uniformly charged disc of radius $R 3$ and surface charge density $σ$ work done by electric field to brought a charge $ϱ$ From centre of disc to distance R along its axis will be :-

$\frac{σ Q R ( 3 - 1 ) )}{2 ϵ _{σ}}$

$\frac{σ Q R}{2 ϵ _{σ}} (2 - 1))$

$\frac{σ Q R}{2 ϵ _{σ}} (3 - 1)$

$\frac{σ Q R}{ϵ _{σ}}$

The electric field due to a uniformly charged disc at a point very distant from the surface of the disc is given by
[ $σ$ is the surface charge density on the disc]

The surface charge density of a thin charged disc of radius $R$ is $σ$ . The value of the electric field at the centre of the disc is $\frac{σ}{2 ϵ _{0}}$ . With respect to the field at the centre, the electric field along the axis at a distance $R$ from the centre of the disc.

An annular disc has inner and outer radius R $_{1}$ and R $_{2}$ respectively. Charge is uniformly distributed. Surface charge density is $σ$ . Find the electric field at any point distant y along the axis of the disc.

A very thin disc is uniformly charged with surface charge density $σ > 0$ . Then the electric field intensity on the axis at the point from which the disc is seen at an solid angle $Ω$ is