There is $S - S$ linkage in:

S_{2} O_{3}^{2 -}

S_{2} O_{4}^{2 -}

S_{2} O_{5}^{2 -}

S_{2} O_{7}^{2 -}

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Solution

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Only $S_{2} O_{7}^{2} -$ has $S - O - S$ bond instead of $S - S$ bond.

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Guides

There is S−S linkage in:

Only S2O27− has S−O−S bond instead of S−S bond.

There is $S - S$ linkage in:

Only $S_{2} O_{7}^{2} -$ has $S - O - S$ bond instead of $S - S$ bond.