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Part of a Whole

Question

This is a whole cake

$\frac{2}{8}$
$\frac{2}{7}$
$\frac{2}{4}$
$\frac{2}{6}$

A

\frac{2}{4}

B

\frac{2}{6}

C

\frac{2}{7}

D

\frac{2}{8}

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Solution

Verified by Toppr

Guru left two parts.
Total parts = 8
$∴$ Required fraction = $\frac{2}{8}$

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