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Correct option is D)

For capacitor is series, equivalent capacitance is given by:

$C_{S}=C_{1}+C_{2}C_{1}C_{2} $

For capacitor is parallel, equivalent capacitance is given by:

$C_{P}=C_{1}+C_{2}$

In the given configuration, equivalent capacitance is given by

$C_{eq}=C_{s}+C$, where $C=4μF$

and $C_{s}=C+CC×C =2C $

$∴C_{eq}=C+2C =6μF$

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