Three charges 1μC, 1μC and 2μC are kept at the vertices A, B and C respestively of an equilateral triangle ABC of 10cm side. The resultant force on the charge at the vertex C is :
0.9 N
1.8 N
2.72 N
3.12 N
A
2.72 N
B
0.9 N
C
1.8 N
D
3.12 N
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Solution
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Component of Forces due to BandAinx direction acting on C cancel out each other ∴Fx=0 in y direction forces add up We get Fy=k(1μC)(2μC)(10×10−2)2×sin60×2
=9×109×1×10−6×2×10−6100×10−4×√32×2
=3⋅1176N
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